C-Kurs/(Pointer) Swapping/Musterlösung: Unterschied zwischen den Versionen
< C-Kurs | (Pointer) Swapping
(Die Seite wurde neu angelegt: „ #include <stdio.h> void swap(int *x, int *y) { int t = *x; *x = *y; *y = t; } int main(){ int i= 1; int j= 2; printf("i: ...“) |
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void swap(int *x, int *y) { | void swap(int *x, int *y) { | ||
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int t = *x; | int t = *x; | ||
*x = *y; | *x = *y; | ||
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int i= 1; | int i= 1; | ||
int j= 2; | int j= 2; | ||
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printf("i: %i j: %i\n", i, j); | printf("i: %i j: %i\n", i, j); | ||
| − | + | ||
swap(&i, &j); | swap(&i, &j); | ||
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printf("i: %i j: %i\n", i, j); | printf("i: %i j: %i\n", i, j); | ||
} | } | ||
Version vom 24. September 2009, 08:40 Uhr
#include <stdio.h>
void swap(int *x, int *y) {
int t = *x;
*x = *y;
*y = t;
}
int main(){
int i= 1;
int j= 2;
printf("i: %i j: %i\n", i, j);
swap(&i, &j);
printf("i: %i j: %i\n", i, j);
}
